Elevation of San Francisco, Francisco Morazán, Honduras
San Francisco, Francisco Morazán, Honduras is 682 m (2,238 ft) above sea level.
San Francisco's height from sea level is 682 metres, or 2,238 feet.
Ground within 5 km
Mean 783 m across the 10 km square centred on the town, 949 m from its lowest cell to its highest.
Cross-section through San Francisco
Ground elevation along two lines through the town, 28.3 km end to end, one cell (about 1 km) per step. The red dot is San Francisco; the vertical scale is the same on both.

Shading is a north-west light over the grid's own slopes. Colour follows elevation: sea level and below, 0–200 m, 500 m, 1,000 m, 2,000 m, 3,500 m, 5,000 m and above.
Towns near San Francisco
| Town | Distance | Direction | Elevation | Compared |
|---|---|---|---|---|
| Villa de San Francisco | 0 km | N | 682 m (2,238 ft) | same |
| Valle de Angeles | 9.6 km | W | 1,330 m (4,364 ft) | +648 m |
| Morocelí (El Paraíso) | 11.2 km | SE | 648 m (2,126 ft) | −34 m |
| San Juan de Flores | 12.6 km | NW | 717 m (2,352 ft) | +35 m |
| San Juancito | 14 km | NW | 1,208 m (3,963 ft) | +526 m |
Where San Francisco is
Latitude 14.17337, longitude -86.952026. Open the map here to read the elevation of any point around the town.
Put this on your site
About this reading
The elevation is the value of the GMTED2010 terrain grid (USGS/NGA, 30 arc-second cells of about 1 km) at San Francisco's recorded coordinates. It is the height of the ground in that cell, not of any building; a town on a slope spans several cells, and the range above says how much that matters here.