Elevation of Minot, North Dakota, United States of America
Minot, North Dakota, United States of America is 510 m (1,673 ft) above sea level.
Minot's height from sea level is 510 metres, or 1,673 feet. GeoNames reads 491 m at the same point (SRTM); Wikidata records 491 m.
Ground within 4 km
Mean 511 m across the 8.5 km square centred on the town, 71 m from its lowest cell to its highest.
Rank by elevation
among the towns of North Dakota, and 103rd of 1,000 in United States of America.
Cross-section through Minot
Ground elevation along two lines through the town, 24 km end to end, one cell (about 1 km) per step. The red dot is Minot; the vertical scale is the same on both.

Shading is a north-west light over the grid's own slopes. Colour follows elevation: sea level and below, 0–200 m, 500 m, 1,000 m, 2,000 m, 3,500 m, 5,000 m and above.
Peaks and passes near Minot
- Twin Buttes, peak at 657 m (2,156 ft), 18.2 km to the SW — 147 m above the town.
- Skinner Hill, peak at 520 m (1,706 ft), 22.8 km to the SE — 10 m above the town.
Summit heights from GeoNames (CC BY 4.0), within 25 km; only summits higher than the town are listed.
Where Minot is
Latitude 48.2325095, longitude -101.2962732. Open the map here to read the elevation of any point around the town.
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About this reading
The elevation is the value of the GMTED2010 terrain grid (USGS/NGA, 30 arc-second cells of about 1 km) at Minot's recorded coordinates. It is the height of the ground in that cell, not of any building; a town on a slope spans several cells, and the range above says how much that matters here. GeoNames' reading of 491 m comes from a finer 90 m SRTM grid at the point it records for the town, which may sit a few hundred metres from ours; the two agreeing to within a few metres is the usual case on flat ground, and a larger gap means the ground is steep. Wikidata's figure is the one its editors cite for the town, often from a survey marker or the town hall.