Elevation of al-Azraq aš-Šamālī, az-Zarqā', Jordan
al-Azraq aš-Šamālī, az-Zarqā', Jordan is 509 m (1,670 ft) above sea level.
al-Azraq aš-Šamālī's height from sea level is 509 metres, or 1,670 feet. GeoNames reads 516 m at the same point (SRTM); Wikidata records 525 m.
Also written: Azraq Shamali الازرق الشمالي.
Ground within 5 km
Mean 512 m across the 9.4 km square centred on the town, 42 m from its lowest cell to its highest.
Cross-section through al-Azraq aš-Šamālī
Ground elevation along two lines through the town, 26.6 km end to end, one cell (about 1 km) per step. The red dot is al-Azraq aš-Šamālī; the vertical scale is the same on both.

Shading is a north-west light over the grid's own slopes. Colour follows elevation: sea level and below, 0–200 m, 500 m, 1,000 m, 2,000 m, 3,500 m, 5,000 m and above.
Where al-Azraq aš-Šamālī is
Latitude 31.83, longitude 36.82. Open the map here to read the elevation of any point around the town.
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About this reading
The elevation is the value of the GMTED2010 terrain grid (USGS/NGA, 30 arc-second cells of about 1 km) at al-Azraq aš-Šamālī's recorded coordinates. It is the height of the ground in that cell, not of any building; a town on a slope spans several cells, and the range above says how much that matters here. GeoNames' reading of 516 m comes from a finer 90 m SRTM grid at the point it records for the town, which may sit a few hundred metres from ours; the two agreeing to within a few metres is the usual case on flat ground, and a larger gap means the ground is steep. Wikidata's figure is the one its editors cite for the town, often from a survey marker or the town hall.